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1414613426119 is a prime number
BaseRepresentation
bin10100100101011101100…
…001111101111111000111
312000020100211201202111021
4110211131201331333013
5141134112014113434
63001510415052011
7204126303503635
oct24453541757707
95006324652437
101414613426119
114a5a30444663
121aa1b3211007
13a352233278a
144c679362355
1526be6063cb4
hex1495d87dfc7

1414613426119 has 2 divisors, whose sum is σ = 1414613426120. Its totient is φ = 1414613426118.

The previous prime is 1414613426117. The next prime is 1414613426159. The reversal of 1414613426119 is 9116243164141.

It is a happy number.

It is a weak prime.

It is an emirp because it is prime and its reverse (9116243164141) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1414613426119 - 21 = 1414613426117 is a prime.

It is a super-2 number, since 2×14146134261192 (a number of 25 digits) contains 22 as substring.

Together with 1414613426117, it forms a pair of twin primes.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1414613426111) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 707306713059 + 707306713060.

It is an arithmetic number, because the mean of its divisors is an integer number (707306713060).

Almost surely, 21414613426119 is an apocalyptic number.

1414613426119 is a deficient number, since it is larger than the sum of its proper divisors (1).

1414613426119 is an equidigital number, since it uses as much as digits as its factorization.

1414613426119 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 124416, while the sum is 43.

The spelling of 1414613426119 in words is "one trillion, four hundred fourteen billion, six hundred thirteen million, four hundred twenty-six thousand, one hundred nineteen".