Base | Representation |
---|---|
bin | 10100101001001011011… |
… | …101010101001111100111 |
3 | 12000121200000221021110112 |
4 | 110221023131111033213 |
5 | 141220300412004241 |
6 | 3003410452243235 |
7 | 204330234066611 |
oct | 24511335251747 |
9 | 5017600837415 |
10 | 1418605188071 |
11 | 4a7699711485 |
12 | 1aab2801051b |
13 | a3a0a32b5b6 |
14 | 4c93756ddb1 |
15 | 26d7b70d1eb |
hex | 14a4b7553e7 |
1418605188071 has 2 divisors, whose sum is σ = 1418605188072. Its totient is φ = 1418605188070.
The previous prime is 1418605188067. The next prime is 1418605188073. The reversal of 1418605188071 is 1708815068141.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1418605188071 - 22 = 1418605188067 is a prime.
Together with 1418605188073, it forms a pair of twin primes.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1418605188073) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 709302594035 + 709302594036.
It is an arithmetic number, because the mean of its divisors is an integer number (709302594036).
Almost surely, 21418605188071 is an apocalyptic number.
1418605188071 is a deficient number, since it is larger than the sum of its proper divisors (1).
1418605188071 is an equidigital number, since it uses as much as digits as its factorization.
1418605188071 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 430080, while the sum is 50.
The spelling of 1418605188071 in words is "one trillion, four hundred eighteen billion, six hundred five million, one hundred eighty-eight thousand, seventy-one".
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