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142001268653 is a prime number
BaseRepresentation
bin1000010000111111101…
…1110110011110101101
3111120112022102212020102
42010033323312132231
54311304311044103
6145122352000445
713154631603536
oct2041773663655
9446468385212
10142001268653
115524a017982
122362bb30125
131051039192a
146c3133768d
153a61784e88
hex210fef67ad

142001268653 has 2 divisors, whose sum is σ = 142001268654. Its totient is φ = 142001268652.

The previous prime is 142001268649. The next prime is 142001268667. The reversal of 142001268653 is 356862100241.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 128523684004 + 13477584649 = 358502^2 + 116093^2 .

It is a cyclic number.

It is not a de Polignac number, because 142001268653 - 22 = 142001268649 is a prime.

It is a super-2 number, since 2×1420012686532 (a number of 23 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (142001268553) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 71000634326 + 71000634327.

It is an arithmetic number, because the mean of its divisors is an integer number (71000634327).

Almost surely, 2142001268653 is an apocalyptic number.

It is an amenable number.

142001268653 is a deficient number, since it is larger than the sum of its proper divisors (1).

142001268653 is an equidigital number, since it uses as much as digits as its factorization.

142001268653 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 69120, while the sum is 38.

Adding to 142001268653 its reverse (356862100241), we get a palindrome (498863368894).

The spelling of 142001268653 in words is "one hundred forty-two billion, one million, two hundred sixty-eight thousand, six hundred fifty-three".