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1420123 is a prime number
BaseRepresentation
bin101011010101101011011
32200011001011
411122231123
5330420443
650234351
715033205
oct5325533
92604034
101420123
1188aa61
125859b7
133a9513
1428d775
151d0b9d
hex15ab5b

1420123 has 2 divisors, whose sum is σ = 1420124. Its totient is φ = 1420122.

The previous prime is 1420121. The next prime is 1420151. The reversal of 1420123 is 3210241.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 1420123 - 21 = 1420121 is a prime.

Together with 1420121, it forms a pair of twin primes.

It is not a weakly prime, because it can be changed into another prime (1420121) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 710061 + 710062.

It is an arithmetic number, because the mean of its divisors is an integer number (710062).

21420123 is an apocalyptic number.

1420123 is a deficient number, since it is larger than the sum of its proper divisors (1).

1420123 is an equidigital number, since it uses as much as digits as its factorization.

1420123 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 48, while the sum is 13.

The square root of 1420123 is about 1191.6891373173. The cubic root of 1420123 is about 112.4023316935.

Adding to 1420123 its reverse (3210241), we get a palindrome (4630364).

It can be divided in two parts, 14201 and 23, that multiplied together give a palindrome (326623).

The spelling of 1420123 in words is "one million, four hundred twenty thousand, one hundred twenty-three".