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142013443220005 = 5738153106348831
BaseRepresentation
bin100000010010100100010100…
…110101100010001000100101
3200121211100112000212201120111
4200102210110311202020211
5122103222012431020010
61222012024122533021
741625063340212310
oct4022442465421045
9617740460781514
10142013443220005
1141282621462205
1213b171a6967171
136131a6c10b406
14270d6b731b977
1511641677ba58a
hex812914d62225

142013443220005 has 16 divisors (see below), whose sum is σ = 194766400134144. Its totient is φ = 97378093491840.

The previous prime is 142013443219979. The next prime is 142013443220027. The reversal of 142013443220005 is 500022344310241.

It is not a de Polignac number, because 142013443220005 - 211 = 142013443217957 is a prime.

It is a Duffinian number.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 51839061 + ... + 54509770.

It is an arithmetic number, because the mean of its divisors is an integer number (12172900008384).

Almost surely, 2142013443220005 is an apocalyptic number.

It is an amenable number.

142013443220005 is a deficient number, since it is larger than the sum of its proper divisors (52752956914139).

142013443220005 is a wasteful number, since it uses less digits than its factorization.

142013443220005 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 106386996.

The product of its (nonzero) digits is 23040, while the sum is 31.

Adding to 142013443220005 its reverse (500022344310241), we get a palindrome (642035787530246).

The spelling of 142013443220005 in words is "one hundred forty-two trillion, thirteen billion, four hundred forty-three million, two hundred twenty thousand, five".

Divisors: 1 5 7 35 38153 190765 267071 1335355 106348831 531744155 744441817 3722209085 4057526949143 20287634745715 28402688644001 142013443220005