Base | Representation |
---|---|
bin | 10100101011011100100… |
… | …101011111011101101011 |
3 | 12000211221201111201121220 |
4 | 110223130211133131223 |
5 | 141240242221222103 |
6 | 3004452231233123 |
7 | 204444460621110 |
oct | 24533445373553 |
9 | 5024851451556 |
10 | 1421040023403 |
11 | 4a8729057290 |
12 | 1ab4a75187a3 |
13 | a40078c3070 |
14 | 4cac8a9a907 |
15 | 26e70365c53 |
hex | 14adc95f76b |
1421040023403 has 64 divisors (see below), whose sum is σ = 2612715635712. Its totient is φ = 663001044480.
The previous prime is 1421040023327. The next prime is 1421040023411. The reversal of 1421040023403 is 3043200401241.
It is not a de Polignac number, because 1421040023403 - 28 = 1421040023147 is a prime.
It is a super-2 number, since 2×14210400234032 (a number of 25 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (1421040023003) by changing a digit.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 6283576 + ... + 6505797.
It is an arithmetic number, because the mean of its divisors is an integer number (40823681808).
Almost surely, 21421040023403 is an apocalyptic number.
1421040023403 is a gapful number since it is divisible by the number (13) formed by its first and last digit.
1421040023403 is a deficient number, since it is larger than the sum of its proper divisors (1191675612309).
1421040023403 is a wasteful number, since it uses less digits than its factorization.
1421040023403 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 12789444.
The product of its (nonzero) digits is 2304, while the sum is 24.
Adding to 1421040023403 its reverse (3043200401241), we get a palindrome (4464240424644).
The spelling of 1421040023403 in words is "one trillion, four hundred twenty-one billion, forty million, twenty-three thousand, four hundred three".
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