Base | Representation |
---|---|
bin | 10100101011100010000… |
… | …000101111110100100111 |
3 | 12000212012001210120122101 |
4 | 110223202000233310213 |
5 | 141240434022220000 |
6 | 3004505242312531 |
7 | 204446644436404 |
oct | 24534200576447 |
9 | 5025161716571 |
10 | 1421131054375 |
11 | 4a877548219a |
12 | 1ab511ab8747 |
13 | a4020716346 |
14 | 4cad6bd52ab |
15 | 26e78347e6a |
hex | 14ae202fd27 |
1421131054375 has 40 divisors (see below), whose sum is σ = 1894033665216. Its totient is φ = 1062216576000.
The previous prime is 1421131054363. The next prime is 1421131054391. The reversal of 1421131054375 is 5734501311241.
It is not a de Polignac number, because 1421131054375 - 29 = 1421131053863 is a prime.
It is a super-2 number, since 2×14211310543752 (a number of 25 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 39 ways as a sum of consecutive naturals, for example, 967474 + ... + 1943776.
Almost surely, 21421131054375 is an apocalyptic number.
1421131054375 is a deficient number, since it is larger than the sum of its proper divisors (472902610841).
1421131054375 is an equidigital number, since it uses as much as digits as its factorization.
1421131054375 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 976477 (or 976462 counting only the distinct ones).
The product of its (nonzero) digits is 50400, while the sum is 37.
The spelling of 1421131054375 in words is "one trillion, four hundred twenty-one billion, one hundred thirty-one million, fifty-four thousand, three hundred seventy-five".
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