142114140401 has 2 divisors, whose sum is σ = 142114140402. Its totient is φ = 142114140400.

The previous prime is 142114140359. The next prime is 142114140403. The reversal of 142114140401 is 104041411241.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 92796390625 + 49317749776 = 304625^2 + 222076^2 .

It is an emirp because it is prime and its reverse (104041411241) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-142114140401 is a prime.

Together with 142114140403, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (142114140403) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 71057070200 + 71057070201.

It is an arithmetic number, because the mean of its divisors is an integer number (71057070201).

Almost surely, 2^142114140401 is an apocalyptic number.

It is an amenable number.

142114140401 is a deficient number, since it is larger than the sum of its proper divisors (1).

142114140401 is an equidigital number, since it uses as much as digits as its factorization.

142114140401 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 512, while the sum is 23.

Adding to 142114140401 its reverse (104041411241), we get a palindrome (246155551642).

The spelling of 142114140401 in words is "one hundred forty-two billion, one hundred fourteen million, one hundred forty thousand, four hundred one".