142120115 has 4 divisors (see below), whose sum is σ = 170544144. Its totient is φ = 113696088.

The previous prime is 142120109. The next prime is 142120141. The reversal of 142120115 is 511021241.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 511021241 = 17 ⋅30060073.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-142120115 is a prime.

It is a super-2 number, since 2×142120115² = 40396254175226450, which contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 142120093 and 142120102.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 14212007 + ... + 14212016.

It is an arithmetic number, because the mean of its divisors is an integer number (42636036).

Almost surely, 2^142120115 is an apocalyptic number.

142120115 is a deficient number, since it is larger than the sum of its proper divisors (28424029).

142120115 is an equidigital number, since it uses as much as digits as its factorization.

142120115 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 28424028.

The product of its (nonzero) digits is 80, while the sum is 17.

The square root of 142120115 is about 11921.4141359153. The cubic root of 142120115 is about 521.8574046681.

Adding to 142120115 its reverse (511021241), we get a palindrome (653141356).

The spelling of 142120115 in words is "one hundred forty-two million, one hundred twenty thousand, one hundred fifteen".