Base | Representation |
---|---|
bin | 10100101011100110001… |
… | …100011110000010110111 |
3 | 12000212100221212011221102 |
4 | 110223212030132002313 |
5 | 141241110004024101 |
6 | 3004520230440315 |
7 | 204451456121114 |
oct | 24534614360267 |
9 | 5025327764842 |
10 | 1421201236151 |
11 | 4a8801057864 |
12 | 1ab53150309b |
13 | a4032119818 |
14 | 4cb0226390b |
15 | 26e7e5ac86b |
hex | 14ae631e0b7 |
1421201236151 has 2 divisors, whose sum is σ = 1421201236152. Its totient is φ = 1421201236150.
The previous prime is 1421201236141. The next prime is 1421201236153. The reversal of 1421201236151 is 1516321021241.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1421201236151 is a prime.
Together with 1421201236153, it forms a pair of twin primes.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1421201236153) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 710600618075 + 710600618076.
It is an arithmetic number, because the mean of its divisors is an integer number (710600618076).
Almost surely, 21421201236151 is an apocalyptic number.
1421201236151 is a deficient number, since it is larger than the sum of its proper divisors (1).
1421201236151 is an equidigital number, since it uses as much as digits as its factorization.
1421201236151 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2880, while the sum is 29.
Adding to 1421201236151 its reverse (1516321021241), we get a palindrome (2937522257392).
The spelling of 1421201236151 in words is "one trillion, four hundred twenty-one billion, two hundred one million, two hundred thirty-six thousand, one hundred fifty-one".
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