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14212140101 = 99114341211
BaseRepresentation
bin11010011110001110…
…00000110001000101
31100200110122112002022
431033013000301011
5213101301440401
610310131252525
71012122124535
oct151707006105
940613575068
1014212140101
116033423235
12290774a145
131456556b73
1498b7394c5
15582a8971b
hex34f1c0c45

14212140101 has 4 divisors (see below), whose sum is σ = 14226482304. Its totient is φ = 14197797900.

The previous prime is 14212140079. The next prime is 14212140133. The reversal of 14212140101 is 10104121241.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 14212140101 - 230 = 13138398277 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 14212140101.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (14212140161) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 7169615 + ... + 7171596.

It is an arithmetic number, because the mean of its divisors is an integer number (3556620576).

Almost surely, 214212140101 is an apocalyptic number.

It is an amenable number.

14212140101 is a deficient number, since it is larger than the sum of its proper divisors (14342203).

14212140101 is an equidigital number, since it uses as much as digits as its factorization.

14212140101 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 14342202.

The product of its (nonzero) digits is 64, while the sum is 17.

Adding to 14212140101 its reverse (10104121241), we get a palindrome (24316261342).

The spelling of 14212140101 in words is "fourteen billion, two hundred twelve million, one hundred forty thousand, one hundred one".

Divisors: 1 991 14341211 14212140101