Base | Representation |
---|---|
bin | 1100111011010000100100… |
… | …1001110010001111111000 |
3 | 1212022200011200022020212201 |
4 | 3032310021021302033320 |
5 | 3330323041241430040 |
6 | 50120554504515544 |
7 | 2664540400453225 |
oct | 316641111621770 |
9 | 55280150266781 |
10 | 14212200342520 |
11 | 458a3a6644794 |
12 | 171650517bbb4 |
13 | 7c1287a81abb |
14 | 371c349dc94c |
15 | 199a5a4b8a9a |
hex | ced092723f8 |
14212200342520 has 64 divisors (see below), whose sum is σ = 33143373612000. Its totient is φ = 5478354620928.
The previous prime is 14212200342503. The next prime is 14212200342533. The reversal of 14212200342520 is 2524300221241.
14212200342520 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 11106415 + ... + 12319774.
Almost surely, 214212200342520 is an apocalyptic number.
14212200342520 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
14212200342520 is an abundant number, since it is smaller than the sum of its proper divisors (18931173269480).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
14212200342520 is a wasteful number, since it uses less digits than its factorization.
14212200342520 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 23426752 (or 23426748 counting only the distinct ones).
The product of its (nonzero) digits is 7680, while the sum is 28.
Adding to 14212200342520 its reverse (2524300221241), we get a palindrome (16736500563761).
The spelling of 14212200342520 in words is "fourteen trillion, two hundred twelve billion, two hundred million, three hundred forty-two thousand, five hundred twenty".
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