142131010433 has 4 divisors (see below), whose sum is σ = 142140792768. Its totient is φ = 142121228100.

The previous prime is 142131010421. The next prime is 142131010499. The reversal of 142131010433 is 334010131241.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 142131010433 - 2¹⁸ = 142130748289 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 142131010399 and 142131010408.

It is not an unprimeable number, because it can be changed into a prime (142131018433) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4869341 + ... + 4898442.

It is an arithmetic number, because the mean of its divisors is an integer number (35535198192).

Almost surely, 2^142131010433 is an apocalyptic number.

It is an amenable number.

142131010433 is a deficient number, since it is larger than the sum of its proper divisors (9782335).

142131010433 is an equidigital number, since it uses as much as digits as its factorization.

142131010433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 9782334.

The product of its (nonzero) digits is 864, while the sum is 23.

Adding to 142131010433 its reverse (334010131241), we get a palindrome (476141141674).

The spelling of 142131010433 in words is "one hundred forty-two billion, one hundred thirty-one million, ten thousand, four hundred thirty-three".