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1421312113310 = 25142131211331
BaseRepresentation
bin10100101011101100110…
…011011011101010011110
312000212122200111022210212
4110223230303123222132
5141241321400111220
63004535231132422
7204454303425125
oct24535463335236
95025580438725
101421312113310
114a88586a8481
121ab562674112
13a404c09b1cb
144cb12c86abc
1526e891b00c5
hex14aeccdba9e

1421312113310 has 8 divisors (see below), whose sum is σ = 2558361803976. Its totient is φ = 568524845320.

The previous prime is 1421312113279. The next prime is 1421312113339. The reversal of 1421312113310 is 133112131241.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a super-2 number, since 2×14213121133102 (a number of 25 digits) contains 22 as substring.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 71065605656 + ... + 71065605675.

It is an arithmetic number, because the mean of its divisors is an integer number (319795225497).

Almost surely, 21421312113310 is an apocalyptic number.

1421312113310 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

1421312113310 is a deficient number, since it is larger than the sum of its proper divisors (1137049690666).

1421312113310 is a wasteful number, since it uses less digits than its factorization.

1421312113310 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 142131211338.

The product of its (nonzero) digits is 432, while the sum is 23.

Adding to 1421312113310 its reverse (133112131241), we get a palindrome (1554424244551).

The spelling of 1421312113310 in words is "one trillion, four hundred twenty-one billion, three hundred twelve million, one hundred thirteen thousand, three hundred ten".

Divisors: 1 2 5 10 142131211331 284262422662 710656056655 1421312113310