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142131340033 is a prime number
BaseRepresentation
bin1000010001011110110…
…0000010001100000001
3111120212101012011121221
42010113230002030001
54312041110340113
6145143315515041
713161101312434
oct2042754021401
9446771164557
10142131340033
1155306488491
12236675b8a81
1310531303a47
146c4471581b
153a6cdc998d
hex2117b02301

142131340033 has 2 divisors, whose sum is σ = 142131340034. Its totient is φ = 142131340032.

The previous prime is 142131340031. The next prime is 142131340079. The reversal of 142131340033 is 330043131241.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 99715113729 + 42416226304 = 315777^2 + 205952^2 .

It is a cyclic number.

It is not a de Polignac number, because 142131340033 - 21 = 142131340031 is a prime.

It is a super-3 number, since 3×1421313400333 (a number of 34 digits) contains 333 as substring.

Together with 142131340031, it forms a pair of twin primes.

It is not a weakly prime, because it can be changed into another prime (142131340031) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 71065670016 + 71065670017.

It is an arithmetic number, because the mean of its divisors is an integer number (71065670017).

Almost surely, 2142131340033 is an apocalyptic number.

It is an amenable number.

142131340033 is a deficient number, since it is larger than the sum of its proper divisors (1).

142131340033 is an equidigital number, since it uses as much as digits as its factorization.

142131340033 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2592, while the sum is 25.

Adding to 142131340033 its reverse (330043131241), we get a palindrome (472174471274).

The spelling of 142131340033 in words is "one hundred forty-two billion, one hundred thirty-one million, three hundred forty thousand, thirty-three".