142131340031 has 2 divisors, whose sum is σ = 142131340032. Its totient is φ = 142131340030.

The previous prime is 142131340007. The next prime is 142131340033. The reversal of 142131340031 is 130043131241.

142131340031 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-142131340031 is a prime.

It is a super-2 number, since 2×142131340031² (a number of 23 digits) contains 22 as substring.

Together with 142131340033, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 142131339979 and 142131340006.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (142131340033) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 71065670015 + 71065670016.

It is an arithmetic number, because the mean of its divisors is an integer number (71065670016).

Almost surely, 2^142131340031 is an apocalyptic number.

142131340031 is a deficient number, since it is larger than the sum of its proper divisors (1).

142131340031 is an equidigital number, since it uses as much as digits as its factorization.

142131340031 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 864, while the sum is 23.

Adding to 142131340031 its reverse (130043131241), we get a palindrome (272174471272).

The spelling of 142131340031 in words is "one hundred forty-two billion, one hundred thirty-one million, three hundred forty thousand, thirty-one".