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14213333000000 = 265623617971
BaseRepresentation
bin1100111011010100110010…
…1010100001111101000000
31212022210002121121012211202
43032311030222201331000
53330332401222000000
650121303125400332
72664610433053511
oct316651452417500
955283077535752
1014213333000000
11458a927a35052
1217167805690a8
137c1408628224
14371d011dca08
15199ac4b50dd5
hexced4caa1f40

14213333000000 has 196 divisors, whose sum is σ = 36788174730336. Its totient is φ = 5438136000000.

The previous prime is 14213332999973. The next prime is 14213333000059. The reversal of 14213333000000 is 33331241.

It is a Harshad number since it is a multiple of its sum of digits (20).

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 27 ways as a sum of consecutive naturals, for example, 22691015 + ... + 23308985.

Almost surely, 214213333000000 is an apocalyptic number.

14213333000000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 14213333000000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (18394087365168).

14213333000000 is an abundant number, since it is smaller than the sum of its proper divisors (22574841730336).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

14213333000000 is an frugal number, since it uses more digits than its factorization.

14213333000000 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 618036 (or 618001 counting only the distinct ones).

The product of its (nonzero) digits is 648, while the sum is 20.

Adding to 14213333000000 its reverse (33331241), we get a palindrome (14213366331241).

The spelling of 14213333000000 in words is "fourteen trillion, two hundred thirteen billion, three hundred thirty-three million", and thus it is an aban number.