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1421382356519 is a prime number
BaseRepresentation
bin10100101011110000111…
…111011000111000100111
312000212211120200001101012
4110223300333120320213
5141241442340402034
63004550220452435
7204456115453616
oct24536077307047
95025746601335
101421382356519
114a8894315214
121ab5820aa11b
13a40607c3638
144cb1c32d87d
1526e90437cce
hex14af0fd8e27

1421382356519 has 2 divisors, whose sum is σ = 1421382356520. Its totient is φ = 1421382356518.

The previous prime is 1421382356497. The next prime is 1421382356521. The reversal of 1421382356519 is 9156532831241.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 1421382356519 - 228 = 1421113921063 is a prime.

It is a super-2 number, since 2×14213823565192 (a number of 25 digits) contains 22 as substring.

Together with 1421382356521, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1421382256519) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 710691178259 + 710691178260.

It is an arithmetic number, because the mean of its divisors is an integer number (710691178260).

Almost surely, 21421382356519 is an apocalyptic number.

1421382356519 is a deficient number, since it is larger than the sum of its proper divisors (1).

1421382356519 is an equidigital number, since it uses as much as digits as its factorization.

1421382356519 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 1555200, while the sum is 50.

The spelling of 1421382356519 in words is "one trillion, four hundred twenty-one billion, three hundred eighty-two million, three hundred fifty-six thousand, five hundred nineteen".