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14214000000 = 2735623103
BaseRepresentation
bin11010011110011100…
…00110110110000000
31100200121011000101110
431033032012312000
5213102241000000
610310235203320
71012144002144
oct151716066600
940617130343
1014214000000
116034483642
1229082a6540
131456a585b5
1498baa1224
15582d05850
hex34f386d80

14214000000 has 448 divisors, whose sum is σ = 49724363520. Its totient is φ = 3590400000.

The previous prime is 14213999983. The next prime is 14214000041. The reversal of 14214000000 is 41241.

It is a Harshad number since it is a multiple of its sum of digits (12).

It is a self number, because there is not a number n which added to its sum of digits gives 14214000000.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 55 ways as a sum of consecutive naturals, for example, 137999949 + ... + 138000051.

Almost surely, 214214000000 is an apocalyptic number.

14214000000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 14214000000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (24862181760).

14214000000 is an abundant number, since it is smaller than the sum of its proper divisors (35510363520).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

14214000000 is an frugal number, since it uses more digits than its factorization.

14214000000 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 173 (or 136 counting only the distinct ones).

The product of its (nonzero) digits is 32, while the sum is 12.

Adding to 14214000000 its reverse (41241), we get a palindrome (14214041241).

The spelling of 14214000000 in words is "fourteen billion, two hundred fourteen million", and thus it is an aban number.