142140113 has 4 divisors (see below), whose sum is σ = 142730148. Its totient is φ = 141550080.

The previous prime is 142140091. The next prime is 142140127. The reversal of 142140113 is 311041241.

It is a happy number.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 48205249 + 93934864 = 6943^2 + 9692^2 .

It is a cyclic number.

It is not a de Polignac number, because 142140113 - 2⁸ = 142139857 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 142140091 and 142140100.

It is not an unprimeable number, because it can be changed into a prime (142140133) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 294656 + ... + 295137.

It is an arithmetic number, because the mean of its divisors is an integer number (35682537).

Almost surely, 2^142140113 is an apocalyptic number.

It is an amenable number.

142140113 is a deficient number, since it is larger than the sum of its proper divisors (590035).

142140113 is an equidigital number, since it uses as much as digits as its factorization.

142140113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 590034.

The product of its (nonzero) digits is 96, while the sum is 17.

The square root of 142140113 is about 11922.2528491892. The cubic root of 142140113 is about 521.8818807129.

Adding to 142140113 its reverse (311041241), we get a palindrome (453181354).

The spelling of 142140113 in words is "one hundred forty-two million, one hundred forty thousand, one hundred thirteen".