142140220133 has 4 divisors (see below), whose sum is σ = 148320229728. Its totient is φ = 135960210540.

The previous prime is 142140220097. The next prime is 142140220151. The reversal of 142140220133 is 331022041241.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 142140220133 - 2²⁰ = 142139171557 is a prime.

It is a Harshad number since it is a multiple of its sum of digits (23), and also a Moran number because the ratio is a prime number: 6180009571 = 142140220133 / (1 + 4 + 2 + 1 + 4 + 0 + 2 + 2 + 0 + 1 + 3 + 3).

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 142140220099 and 142140220108.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (142140220163) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3090004763 + ... + 3090004808.

It is an arithmetic number, because the mean of its divisors is an integer number (37080057432).

Almost surely, 2^142140220133 is an apocalyptic number.

It is an amenable number.

142140220133 is a deficient number, since it is larger than the sum of its proper divisors (6180009595).

142140220133 is an equidigital number, since it uses as much as digits as its factorization.

142140220133 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 6180009594.

The product of its (nonzero) digits is 1152, while the sum is 23.

Adding to 142140220133 its reverse (331022041241), we get a palindrome (473162261374).

The spelling of 142140220133 in words is "one hundred forty-two billion, one hundred forty million, two hundred twenty thousand, one hundred thirty-three".