Search a number
-
+
14223212243333 = 42413353740213
BaseRepresentation
bin1100111011111001100110…
…0000110110100110000101
31212100201121010010202221222
43032332121200312212011
53331013114313241313
650130015320050125
72665410313203302
oct316763140664605
955321533122858
1014223212243333
114594037570865
121718679003945
137c23212b5242
1437259b2ca0a9
15199ea2109208
hexcef99836985

14223212243333 has 4 divisors (see below), whose sum is σ = 14226565987788. Its totient is φ = 14219858498880.

The previous prime is 14223212243263. The next prime is 14223212243351. The reversal of 14223212243333 is 33334221232241.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 6271528507204 + 7951683736129 = 2504302^2 + 2819873^2 .

It is a cyclic number.

It is not a de Polignac number, because 14223212243333 - 236 = 14154492766597 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 14223212243293 and 14223212243302.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (14223212243353) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1676865866 + ... + 1676874347.

It is an arithmetic number, because the mean of its divisors is an integer number (3556641496947).

Almost surely, 214223212243333 is an apocalyptic number.

It is an amenable number.

14223212243333 is a deficient number, since it is larger than the sum of its proper divisors (3353744455).

14223212243333 is an equidigital number, since it uses as much as digits as its factorization.

14223212243333 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3353744454.

The product of its digits is 124416, while the sum is 35.

Adding to 14223212243333 its reverse (33334221232241), we get a palindrome (47557433475574).

The spelling of 14223212243333 in words is "fourteen trillion, two hundred twenty-three billion, two hundred twelve million, two hundred forty-three thousand, three hundred thirty-three".

Divisors: 1 4241 3353740213 14223212243333