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14230042112021 is a prime number
BaseRepresentation
bin1100111100010011000010…
…0110101111000000010101
31212101101020002202001110112
43033010300212233000111
53331121111240041041
650133105135532405
72666041465136021
oct317046046570025
955341202661415
1014230042112021
114596a2188323a
121719a6438a105
137c2b6c291168
14372a483db381
1519a251a18deb
hexcf1309af015

14230042112021 has 2 divisors, whose sum is σ = 14230042112022. Its totient is φ = 14230042112020.

The previous prime is 14230042111969. The next prime is 14230042112023. The reversal of 14230042112021 is 12021124003241.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 8068377759121 + 6161664352900 = 2840489^2 + 2482270^2 .

It is an emirp because it is prime and its reverse (12021124003241) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 14230042112021 - 226 = 14229975003157 is a prime.

Together with 14230042112023, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (14230042112023) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7115021056010 + 7115021056011.

It is an arithmetic number, because the mean of its divisors is an integer number (7115021056011).

Almost surely, 214230042112021 is an apocalyptic number.

It is an amenable number.

14230042112021 is a deficient number, since it is larger than the sum of its proper divisors (1).

14230042112021 is an equidigital number, since it uses as much as digits as its factorization.

14230042112021 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 768, while the sum is 23.

Adding to 14230042112021 its reverse (12021124003241), we get a palindrome (26251166115262).

The spelling of 14230042112021 in words is "fourteen trillion, two hundred thirty billion, forty-two million, one hundred twelve thousand, twenty-one".