Base | Representation |
---|---|
bin | 100000010111000010111110… |
… | …011010111001001111111111 |
3 | 200122220202222021222002002001 |
4 | 200113002332122321033333 |
5 | 122123242340121312120 |
6 | 1222405245420043131 |
7 | 41656240531426000 |
oct | 4027027632711777 |
9 | 618822867862061 |
10 | 142321231041535 |
11 | 41391105686047 |
12 | 13b669843934a7 |
13 | 6154ab0520830 |
14 | 27205548951a7 |
15 | 116c17da11e0a |
hex | 8170be6b93ff |
142321231041535 has 64 divisors (see below), whose sum is σ = 216491812992000. Its totient is φ = 89242733252736.
The previous prime is 142321231041529. The next prime is 142321231041599. The reversal of 142321231041535 is 535140132123241.
It is not a de Polignac number, because 142321231041535 - 213 = 142321231033343 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 142321231041494 and 142321231041503.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 27444105 + ... + 32215234.
It is an arithmetic number, because the mean of its divisors is an integer number (3382684578000).
Almost surely, 2142321231041535 is an apocalyptic number.
142321231041535 is a deficient number, since it is larger than the sum of its proper divisors (74170581950465).
142321231041535 is a wasteful number, since it uses less digits than its factorization.
142321231041535 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 59659485 (or 59659471 counting only the distinct ones).
The product of its (nonzero) digits is 86400, while the sum is 37.
Adding to 142321231041535 its reverse (535140132123241), we get a palindrome (677461363164776).
The spelling of 142321231041535 in words is "one hundred forty-two trillion, three hundred twenty-one billion, two hundred thirty-one million, forty-one thousand, five hundred thirty-five".
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