Base | Representation |
---|---|
bin | 1000010010010001100… |
… | …0100011010000010101 |
3 | 111121102012222111201110 |
4 | 2010210120203100111 |
5 | 4313010122231110 |
6 | 145220405045233 |
7 | 13166265616215 |
oct | 2044430432025 |
9 | 447365874643 |
10 | 142344336405 |
11 | 55405737847 |
12 | 237069b6819 |
13 | 1056648b6bb |
14 | 6c64b1c245 |
15 | 3a8194ea20 |
hex | 2124623415 |
142344336405 has 8 divisors (see below), whose sum is σ = 227750938272. Its totient is φ = 75916979408.
The previous prime is 142344336391. The next prime is 142344336457. The reversal of 142344336405 is 504633443241.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 142344336405 - 25 = 142344336373 is a prime.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (13) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 4744811199 + ... + 4744811228.
It is an arithmetic number, because the mean of its divisors is an integer number (28468867284).
Almost surely, 2142344336405 is an apocalyptic number.
142344336405 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
It is an amenable number.
142344336405 is a deficient number, since it is larger than the sum of its proper divisors (85406601867).
142344336405 is an equidigital number, since it uses as much as digits as its factorization.
142344336405 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 9489622435.
The product of its (nonzero) digits is 414720, while the sum is 39.
Adding to 142344336405 its reverse (504633443241), we get a palindrome (646977779646).
The spelling of 142344336405 in words is "one hundred forty-two billion, three hundred forty-four million, three hundred thirty-six thousand, four hundred five".
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