Base | Representation |
---|---|
bin | 100000010111100010011101… |
… | …100101111000000000111111 |
3 | 200200001000020111111122022111 |
4 | 200113202131211320000333 |
5 | 122124321110220312203 |
6 | 1222433000315354451 |
7 | 41661545412060031 |
oct | 4027423545700077 |
9 | 620030214448274 |
10 | 142355040010303 |
11 | 413a448499674a |
12 | 13b7143aa52a27 |
13 | 615803aa703b3 |
14 | 2722040b27c51 |
15 | 116ceabc2926d |
hex | 81789d97803f |
142355040010303 has 12 divisors (see below), whose sum is σ = 154315707517008. Its totient is φ = 130865371909440.
The previous prime is 142355040010297. The next prime is 142355040010357. The reversal of 142355040010303 is 303010040553241.
It is a de Polignac number, because none of the positive numbers 2k-142355040010303 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (142355040019303) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 2264388763 + ... + 2264451628.
It is an arithmetic number, because the mean of its divisors is an integer number (12859642293084).
Almost surely, 2142355040010303 is an apocalyptic number.
142355040010303 is a deficient number, since it is larger than the sum of its proper divisors (11960667506705).
142355040010303 is an equidigital number, since it uses as much as digits as its factorization.
142355040010303 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 4528840494 (or 4528840451 counting only the distinct ones).
The product of its (nonzero) digits is 21600, while the sum is 31.
Adding to 142355040010303 its reverse (303010040553241), we get a palindrome (445365080563544).
The spelling of 142355040010303 in words is "one hundred forty-two trillion, three hundred fifty-five billion, forty million, ten thousand, three hundred three".
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