14241300341 has 2 divisors, whose sum is σ = 14241300342. Its totient is φ = 14241300340.

The previous prime is 14241300319. The next prime is 14241300343. The reversal of 14241300341 is 14300314241.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 14035377841 + 205922500 = 118471^2 + 14350^2 .

It is a cyclic number.

It is not a de Polignac number, because 14241300341 - 2¹⁸ = 14241038197 is a prime.

Together with 14241300343, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (14241300343) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7120650170 + 7120650171.

It is an arithmetic number, because the mean of its divisors is an integer number (7120650171).

Almost surely, 2^14241300341 is an apocalyptic number.

It is an amenable number.

14241300341 is a deficient number, since it is larger than the sum of its proper divisors (1).

14241300341 is an equidigital number, since it uses as much as digits as its factorization.

14241300341 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1152, while the sum is 23.

Adding to 14241300341 its reverse (14300314241), we get a palindrome (28541614582).

The spelling of 14241300341 in words is "fourteen billion, two hundred forty-one million, three hundred thousand, three hundred forty-one".