Base | Representation |
---|---|
bin | 11010100001111010… |
… | …01010000110100111 |
3 | 1100202121221000122001 |
4 | 31100331022012213 |
5 | 213132214030320 |
6 | 10313155150131 |
7 | 1012646306635 |
oct | 152075120647 |
9 | 40677830561 |
10 | 14243111335 |
11 | 60499573a2 |
12 | 2915ba5347 |
13 | 145caabc3b |
14 | 9918bc355 |
15 | 58565620a |
hex | 350f4a1a7 |
14243111335 has 8 divisors (see below), whose sum is σ = 17553672576. Its totient is φ = 11086529760.
The previous prime is 14243111273. The next prime is 14243111339. The reversal of 14243111335 is 53311134241.
14243111335 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 14243111335 - 217 = 14242980263 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (14243111339) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 38494711 + ... + 38495080.
It is an arithmetic number, because the mean of its divisors is an integer number (2194209072).
Almost surely, 214243111335 is an apocalyptic number.
14243111335 is a deficient number, since it is larger than the sum of its proper divisors (3310561241).
14243111335 is an equidigital number, since it uses as much as digits as its factorization.
14243111335 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 76989833.
The product of its digits is 4320, while the sum is 28.
Adding to 14243111335 its reverse (53311134241), we get a palindrome (67554245576).
The spelling of 14243111335 in words is "fourteen billion, two hundred forty-three million, one hundred eleven thousand, three hundred thirty-five".
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