Base | Representation |
---|---|
bin | 1100111101000100011110… |
… | …0111001010101001101010 |
3 | 1212102122110222021011122110 |
4 | 3033101013213022221222 |
5 | 3331330301112044424 |
6 | 50143142045103150 |
7 | 3000021400635426 |
oct | 317210747125152 |
9 | 55378428234573 |
10 | 14243313003114 |
11 | 45a1611960128 |
12 | 1720548857ab6 |
13 | 7c41a580b440 |
14 | 373546b1db86 |
15 | 19a77bb29c29 |
hex | cf4479caa6a |
14243313003114 has 16 divisors (see below), whose sum is σ = 30677904929952. Its totient is φ = 4382557847088.
The previous prime is 14243313003113. The next prime is 14243313003173. The reversal of 14243313003114 is 41130031334241.
It is a super-3 number, since 3×142433130031143 (a number of 40 digits) contains 333 as substring.
It is not an unprimeable number, because it can be changed into a prime (14243313003113) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 91303288404 + ... + 91303288559.
It is an arithmetic number, because the mean of its divisors is an integer number (1917369058122).
Almost surely, 214243313003114 is an apocalyptic number.
14243313003114 is an abundant number, since it is smaller than the sum of its proper divisors (16434591926838).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
14243313003114 is a wasteful number, since it uses less digits than its factorization.
14243313003114 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 182606576981.
The product of its (nonzero) digits is 10368, while the sum is 30.
Adding to 14243313003114 its reverse (41130031334241), we get a palindrome (55373344337355).
The spelling of 14243313003114 in words is "fourteen trillion, two hundred forty-three billion, three hundred thirteen million, three thousand, one hundred fourteen".
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