14244555133 has 2 divisors, whose sum is σ = 14244555134. Its totient is φ = 14244555132.

The previous prime is 14244555131. The next prime is 14244555181. The reversal of 14244555133 is 33155544241.

14244555133 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 11341824004 + 2902731129 = 106498^2 + 53877^2 .

It is a cyclic number.

It is not a de Polignac number, because 14244555133 - 2¹ = 14244555131 is a prime.

Together with 14244555131, it forms a pair of twin primes.

It is a junction number, because it is equal to n+sod(n) for n = 14244555092 and 14244555101.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (14244555131) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7122277566 + 7122277567.

It is an arithmetic number, because the mean of its divisors is an integer number (7122277567).

Almost surely, 2^14244555133 is an apocalyptic number.

It is an amenable number.

14244555133 is a deficient number, since it is larger than the sum of its proper divisors (1).

14244555133 is an equidigital number, since it uses as much as digits as its factorization.

14244555133 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 144000, while the sum is 37.

The spelling of 14244555133 in words is "fourteen billion, two hundred forty-four million, five hundred fifty-five thousand, one hundred thirty-three".