Base | Representation |
---|---|
bin | 10100101111001111010… |
… | …111100000010100110101 |
3 | 12001020110120221120111010 |
4 | 110233033113200110311 |
5 | 141322112441023110 |
6 | 3010404334102433 |
7 | 204650430335040 |
oct | 24571727402465 |
9 | 5036416846433 |
10 | 1425113220405 |
11 | 4aa4292954a6 |
12 | 1b024364aa19 |
13 | a45067324c4 |
14 | 4cd93a25c57 |
15 | 2710cc49020 |
hex | 14bcf5e0535 |
1425113220405 has 32 divisors (see below), whose sum is σ = 2606738577408. Its totient is φ = 651276014400.
The previous prime is 1425113220397. The next prime is 1425113220451. The reversal of 1425113220405 is 5040223115241.
It is not a de Polignac number, because 1425113220405 - 23 = 1425113220397 is a prime.
It is a super-2 number, since 2×14251132204052 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 1791631 + ... + 2461740.
It is an arithmetic number, because the mean of its divisors is an integer number (81460580544).
Almost surely, 21425113220405 is an apocalyptic number.
1425113220405 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
It is an amenable number.
1425113220405 is a deficient number, since it is larger than the sum of its proper divisors (1181625357003).
1425113220405 is a wasteful number, since it uses less digits than its factorization.
1425113220405 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4256577.
The product of its (nonzero) digits is 9600, while the sum is 30.
Adding to 1425113220405 its reverse (5040223115241), we get a palindrome (6465336335646).
The spelling of 1425113220405 in words is "one trillion, four hundred twenty-five billion, one hundred thirteen million, two hundred twenty thousand, four hundred five".
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