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14251141213 is a prime number
BaseRepresentation
bin11010100010110111…
…10010100001011101
31100210012000222112221
431101123302201131
5213141243004323
610314043225341
71013104462441
oct152133624135
940705028487
1014251141213
116053441361
122918818251
131461660b4a
149929ac821
155861e055d
hex3516f285d

14251141213 has 2 divisors, whose sum is σ = 14251141214. Its totient is φ = 14251141212.

The previous prime is 14251141211. The next prime is 14251141321. The reversal of 14251141213 is 31214115241.

It is a happy number.

Together with next prime (14251141321) it forms an Ormiston pair, because they use the same digits, order apart.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 11360788569 + 2890352644 = 106587^2 + 53762^2 .

It is a cyclic number.

It is not a de Polignac number, because 14251141213 - 21 = 14251141211 is a prime.

It is a super-2 number, since 2×142511412132 (a number of 21 digits) contains 22 as substring.

Together with 14251141211, it forms a pair of twin primes.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (14251141211) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7125570606 + 7125570607.

It is an arithmetic number, because the mean of its divisors is an integer number (7125570607).

Almost surely, 214251141213 is an apocalyptic number.

It is an amenable number.

14251141213 is a deficient number, since it is larger than the sum of its proper divisors (1).

14251141213 is an equidigital number, since it uses as much as digits as its factorization.

14251141213 is an evil number, because the sum of its binary digits is even.

The product of its digits is 960, while the sum is 25.

Adding to 14251141213 its reverse (31214115241), we get a palindrome (45465256454).

The spelling of 14251141213 in words is "fourteen billion, two hundred fifty-one million, one hundred forty-one thousand, two hundred thirteen".