14253034111 has 2 divisors, whose sum is σ = 14253034112. Its totient is φ = 14253034110.

The previous prime is 14253034099. The next prime is 14253034121. The reversal of 14253034111 is 11143035241.

14253034111 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 14253034111 - 2¹¹ = 14253032063 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (14253034121) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7126517055 + 7126517056.

It is an arithmetic number, because the mean of its divisors is an integer number (7126517056).

Almost surely, 2^14253034111 is an apocalyptic number.

14253034111 is a deficient number, since it is larger than the sum of its proper divisors (1).

14253034111 is an equidigital number, since it uses as much as digits as its factorization.

14253034111 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1440, while the sum is 25.

Adding to 14253034111 its reverse (11143035241), we get a palindrome (25396069352).

The spelling of 14253034111 in words is "fourteen billion, two hundred fifty-three million, thirty-four thousand, one hundred eleven".