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14253034121 is a prime number
BaseRepresentation
bin11010100011000110…
…00000101010001001
31100210022121011010122
431101203000222021
5213142234042441
610314151553025
71013126535224
oct152143005211
940708534118
1014253034121
116054514547
12291938b775
131461b74601
14992d425bb
1558646634b
hex3518c0a89

14253034121 has 2 divisors, whose sum is σ = 14253034122. Its totient is φ = 14253034120.

The previous prime is 14253034111. The next prime is 14253034123. The reversal of 14253034121 is 12143035241.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 12215775625 + 2037258496 = 110525^2 + 45136^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-14253034121 is a prime.

Together with 14253034123, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (14253034123) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7126517060 + 7126517061.

It is an arithmetic number, because the mean of its divisors is an integer number (7126517061).

Almost surely, 214253034121 is an apocalyptic number.

It is an amenable number.

14253034121 is a deficient number, since it is larger than the sum of its proper divisors (1).

14253034121 is an equidigital number, since it uses as much as digits as its factorization.

14253034121 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2880, while the sum is 26.

Adding to 14253034121 its reverse (12143035241), we get a palindrome (26396069362).

The spelling of 14253034121 in words is "fourteen billion, two hundred fifty-three million, thirty-four thousand, one hundred twenty-one".