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142564524343 is a prime number
BaseRepresentation
bin1000010011000110000…
…0100000000100110111
3111121222120022012210021
42010301200200010313
54313433004234333
6145254312310011
713204611314443
oct2046140400467
9447876265707
10142564524343
1155508a5924a
12237686a2307
131059cc93817
146c86077823
153a95e4582d
hex2131820137

142564524343 has 2 divisors, whose sum is σ = 142564524344. Its totient is φ = 142564524342.

The previous prime is 142564524341. The next prime is 142564524353. The reversal of 142564524343 is 343425465241.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 142564524343 - 21 = 142564524341 is a prime.

It is a super-2 number, since 2×1425645243432 (a number of 23 digits) contains 22 as substring.

Together with 142564524341, it forms a pair of twin primes.

It is a self number, because there is not a number n which added to its sum of digits gives 142564524343.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (142564524341) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 71282262171 + 71282262172.

It is an arithmetic number, because the mean of its divisors is an integer number (71282262172).

Almost surely, 2142564524343 is an apocalyptic number.

142564524343 is a deficient number, since it is larger than the sum of its proper divisors (1).

142564524343 is an equidigital number, since it uses as much as digits as its factorization.

142564524343 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 1382400, while the sum is 43.

Adding to 142564524343 its reverse (343425465241), we get a palindrome (485989989584).

The spelling of 142564524343 in words is "one hundred forty-two billion, five hundred sixty-four million, five hundred twenty-four thousand, three hundred forty-three".