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142613159413 is a prime number
BaseRepresentation
bin1000010011010001101…
…0000001110111110101
3111122002221211010120011
42010310122001313311
54314032432100123
6145303210540221
713206041565604
oct2046432016765
9448087733504
10142613159413
115553345751a
1223780a37671
13105aa09187a
146c8c6d7a3b
153a9a350e0d
hex2134681df5

142613159413 has 2 divisors, whose sum is σ = 142613159414. Its totient is φ = 142613159412.

The previous prime is 142613159411. The next prime is 142613159453. The reversal of 142613159413 is 314951316241.

It is an a-pointer prime, because the next prime (142613159453) can be obtained adding 142613159413 to its sum of digits (40).

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 81477135364 + 61136024049 = 285442^2 + 247257^2 .

It is an emirp because it is prime and its reverse (314951316241) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 142613159413 - 21 = 142613159411 is a prime.

Together with 142613159411, it forms a pair of twin primes.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (142613159411) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 71306579706 + 71306579707.

It is an arithmetic number, because the mean of its divisors is an integer number (71306579707).

Almost surely, 2142613159413 is an apocalyptic number.

It is an amenable number.

142613159413 is a deficient number, since it is larger than the sum of its proper divisors (1).

142613159413 is an equidigital number, since it uses as much as digits as its factorization.

142613159413 is an evil number, because the sum of its binary digits is even.

The product of its digits is 77760, while the sum is 40.

The spelling of 142613159413 in words is "one hundred forty-two billion, six hundred thirteen million, one hundred fifty-nine thousand, four hundred thirteen".