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14300312340103 is a prime number
BaseRepresentation
bin1101000000011000110100…
…0010011000011010000111
31212122002121100120111120121
43100012031002120122013
53333244014424340403
650225250042442411
73004110033206446
oct320061502303207
955562540514517
1014300312340103
1146138015646a9
12172b5b5803407
137c968a6b138a
143761d2c76d5d
1519beb5c073bd
hexd018d098687

14300312340103 has 2 divisors, whose sum is σ = 14300312340104. Its totient is φ = 14300312340102.

The previous prime is 14300312340073. The next prime is 14300312340133. The reversal of 14300312340103 is 30104321300341.

It is a balanced prime because it is at equal distance from previous prime (14300312340073) and next prime (14300312340133).

It is an emirp because it is prime and its reverse (30104321300341) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 14300312340103 - 217 = 14300312209031 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (14300312340133) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7150156170051 + 7150156170052.

It is an arithmetic number, because the mean of its divisors is an integer number (7150156170052).

Almost surely, 214300312340103 is an apocalyptic number.

14300312340103 is a deficient number, since it is larger than the sum of its proper divisors (1).

14300312340103 is an equidigital number, since it uses as much as digits as its factorization.

14300312340103 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2592, while the sum is 25.

Adding to 14300312340103 its reverse (30104321300341), we get a palindrome (44404633640444).

The spelling of 14300312340103 in words is "fourteen trillion, three hundred billion, three hundred twelve million, three hundred forty thousand, one hundred three".