14310021413 has 4 divisors (see below), whose sum is σ = 14312683200. Its totient is φ = 14307359628.

The previous prime is 14310021409. The next prime is 14310021421. The reversal of 14310021413 is 31412001341.

14310021413 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 31412001341 = 7 ⋅4487428763.

It is a cyclic number.

It is not a de Polignac number, because 14310021413 - 2² = 14310021409 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (14310021463) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1322813 + ... + 1333586.

It is an arithmetic number, because the mean of its divisors is an integer number (3578170800).

Almost surely, 2^14310021413 is an apocalyptic number.

It is an amenable number.

14310021413 is a deficient number, since it is larger than the sum of its proper divisors (2661787).

14310021413 is an equidigital number, since it uses as much as digits as its factorization.

14310021413 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2661786.

The product of its (nonzero) digits is 288, while the sum is 20.

Adding to 14310021413 its reverse (31412001341), we get a palindrome (45722022754).

The spelling of 14310021413 in words is "fourteen billion, three hundred ten million, twenty-one thousand, four hundred thirteen".