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143100343142 = 271550171571
BaseRepresentation
bin1000010101000101110…
…0011111001101100110
3111200100220112121222222
42011101130133031212
54321032141440032
6145423412552342
713224105563411
oct2052134371546
9450326477888
10143100343142
115576345a8a9
12238980226b2
1310656caa273
146cd72b4b78
153ac7ed6a12
hex215171f366

143100343142 has 4 divisors (see below), whose sum is σ = 214650514716. Its totient is φ = 71550171570.

The previous prime is 143100343121. The next prime is 143100343159. The reversal of 143100343142 is 241343001341.

It is a happy number.

143100343142 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 241343001341 = 1318564846257.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 35775085784 + ... + 35775085787.

It is an arithmetic number, because the mean of its divisors is an integer number (53662628679).

Almost surely, 2143100343142 is an apocalyptic number.

143100343142 is a deficient number, since it is larger than the sum of its proper divisors (71550171574).

143100343142 is an equidigital number, since it uses as much as digits as its factorization.

143100343142 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 71550171573.

The product of its (nonzero) digits is 3456, while the sum is 26.

Adding to 143100343142 its reverse (241343001341), we get a palindrome (384443344483).

The spelling of 143100343142 in words is "one hundred forty-three billion, one hundred million, three hundred forty-three thousand, one hundred forty-two".

Divisors: 1 2 71550171571 143100343142