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143103310045 = 567709422701
BaseRepresentation
bin1000010101000110011…
…1110011100011011101
3111200101010010100211021
42011101213303203131
54321033421410140
6145424000324141
713224143031313
oct2052147634335
9450333110737
10143103310045
11557650a6993
1223899013651
13106577a8827
146cd78480b3
153ac83c0b4a
hex21519f38dd

143103310045 has 8 divisors (see below), whose sum is σ = 171726914520. Its totient is φ = 114480686400.

The previous prime is 143103310003. The next prime is 143103310057. The reversal of 143103310045 is 540013301341.

It can be written as a sum of positive squares in 4 ways, for example, as 17632918521 + 125470391524 = 132789^2 + 354218^2 .

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 143103310045 - 27 = 143103309917 is a prime.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 127195 + ... + 549895.

It is an arithmetic number, because the mean of its divisors is an integer number (21465864315).

Almost surely, 2143103310045 is an apocalyptic number.

It is an amenable number.

143103310045 is a deficient number, since it is larger than the sum of its proper divisors (28623604475).

143103310045 is an equidigital number, since it uses as much as digits as its factorization.

143103310045 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 490415.

The product of its (nonzero) digits is 2160, while the sum is 25.

Adding to 143103310045 its reverse (540013301341), we get a palindrome (683116611386).

The spelling of 143103310045 in words is "one hundred forty-three billion, one hundred three million, three hundred ten thousand, forty-five".

Divisors: 1 5 67709 338545 422701 2113505 28620662009 143103310045