Base | Representation |
---|---|
bin | 10100110100110100000… |
… | …111100000000111110100 |
3 | 12001210220201021211201220 |
4 | 110310310013200013310 |
5 | 141421342203211010 |
6 | 3013234303150340 |
7 | 205251645316455 |
oct | 24646407400764 |
9 | 5053821254656 |
10 | 1431098491380 |
11 | 501a1a876138 |
12 | 1b1433ba53b0 |
13 | a4c4b74206c |
14 | 4d3a08bd12c |
15 | 2735d422970 |
hex | 14d341e01f4 |
1431098491380 has 48 divisors (see below), whose sum is σ = 4063513474944. Its totient is φ = 376251245440.
The previous prime is 1431098491369. The next prime is 1431098491391. The reversal of 1431098491380 is 831948901341.
It is an interprime number because it is at equal distance from previous prime (1431098491369) and next prime (1431098491391).
It is a super-2 number, since 2×14310984913802 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 167965047 + ... + 167973566.
It is an arithmetic number, because the mean of its divisors is an integer number (84656530728).
Almost surely, 21431098491380 is an apocalyptic number.
1431098491380 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
1431098491380 is an abundant number, since it is smaller than the sum of its proper divisors (2632414983564).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
1431098491380 is a wasteful number, since it uses less digits than its factorization.
1431098491380 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 335938696 (or 335938694 counting only the distinct ones).
The product of its (nonzero) digits is 746496, while the sum is 51.
The spelling of 1431098491380 in words is "one trillion, four hundred thirty-one billion, ninety-eight million, four hundred ninety-one thousand, three hundred eighty".
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