Base | Representation |
---|---|
bin | 11010101010000000… |
… | …01011010000001101 |
3 | 1100221100200200221002 |
4 | 31111000023100031 |
5 | 213302104330331 |
6 | 10324022350045 |
7 | 1014432406064 |
oct | 152500132015 |
9 | 40840620832 |
10 | 14311011341 |
11 | 6084213700 |
12 | 293488b325 |
13 | 1470b93963 |
14 | 99a9151db |
15 | 58b5b99cb |
hex | 35500b40d |
14311011341 has 24 divisors (see below), whose sum is σ = 16154890752. Its totient is φ = 12661941600.
The previous prime is 14311011329. The next prime is 14311011361.
14311011341 is nontrivially palindromic in base 10.
It is a de Polignac number, because none of the positive numbers 2k-14311011341 is a prime.
It is a Curzon number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (14311011301) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (13) of ones.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 1022396 + ... + 1036298.
It is an arithmetic number, because the mean of its divisors is an integer number (673120448).
Almost surely, 214311011341 is an apocalyptic number.
14311011341 is a gapful number since it is divisible by the number (11) formed by its first and last digit.
It is an amenable number.
14311011341 is a deficient number, since it is larger than the sum of its proper divisors (1843879411).
14311011341 is a wasteful number, since it uses less digits than its factorization.
14311011341 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 14153 (or 14142 counting only the distinct ones).
The product of its (nonzero) digits is 144, while the sum is 20.
It can be divided in two parts, 143110 and 11341, that added together give a palindrome (154451).
The spelling of 14311011341 in words is "fourteen billion, three hundred eleven million, eleven thousand, three hundred forty-one".
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