Base | Representation |
---|---|
bin | 1101000001000001001000… |
… | …1101010111101110010000 |
3 | 1212200010112201012002002221 |
4 | 3100100102031113232100 |
5 | 3333433201422301300 |
6 | 50234240110350424 |
7 | 3004642206234424 |
oct | 320202215275620 |
9 | 55603481162087 |
10 | 14311136525200 |
11 | 4618356529119 |
12 | 17317167bb414 |
13 | 7ca6c406ba28 |
14 | 37693c65cb84 |
15 | 19c3eb11831a |
hex | d0412357b90 |
14311136525200 has 60 divisors (see below), whose sum is σ = 34768825874820. Its totient is φ = 5660134881280.
The previous prime is 14311136525183. The next prime is 14311136525249. The reversal of 14311136525200 is 252563111341.
It can be written as a sum of positive squares in 6 ways, for example, as 13935330304 + 14297201194896 = 118048^2 + 3781164^2 .
It is an unprimeable number.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 200963509 + ... + 201034708.
It is an arithmetic number, because the mean of its divisors is an integer number (579480431247).
Almost surely, 214311136525200 is an apocalyptic number.
14311136525200 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
14311136525200 is an abundant number, since it is smaller than the sum of its proper divisors (20457689349620).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
14311136525200 is a wasteful number, since it uses less digits than its factorization.
14311136525200 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 401998324 (or 401998313 counting only the distinct ones).
The product of its (nonzero) digits is 21600, while the sum is 34.
Adding to 14311136525200 its reverse (252563111341), we get a palindrome (14563699636541).
The spelling of 14311136525200 in words is "fourteen trillion, three hundred eleven billion, one hundred thirty-six million, five hundred twenty-five thousand, two hundred".
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