Base | Representation |
---|---|
bin | 1101000001000001001001… |
… | …1011111000111001100111 |
3 | 1212200010112222100102211121 |
4 | 3100100102123320321213 |
5 | 3333433203411043421 |
6 | 50234240324114411 |
7 | 3004642253465401 |
oct | 320202233707147 |
9 | 55603488312747 |
10 | 14311140331111 |
11 | 46183586985a8 |
12 | 1731717b35a07 |
13 | 7ca6c4aa2150 |
14 | 37693cd6db71 |
15 | 19c3eb61ad41 |
hex | d04126f8e67 |
14311140331111 has 32 divisors (see below), whose sum is σ = 17029977632640. Its totient is φ = 11891314642944.
The previous prime is 14311140331091. The next prime is 14311140331123. The reversal of 14311140331111 is 11113304111341.
It is not a de Polignac number, because 14311140331111 - 25 = 14311140331079 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (14311140331141) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 47084835 + ... + 47387803.
It is an arithmetic number, because the mean of its divisors is an integer number (532186801020).
Almost surely, 214311140331111 is an apocalyptic number.
14311140331111 is a deficient number, since it is larger than the sum of its proper divisors (2718837301529).
14311140331111 is a wasteful number, since it uses less digits than its factorization.
14311140331111 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 312315.
The product of its (nonzero) digits is 432, while the sum is 25.
Adding to 14311140331111 its reverse (11113304111341), we get a palindrome (25424444442452).
The spelling of 14311140331111 in words is "fourteen trillion, three hundred eleven billion, one hundred forty million, three hundred thirty-one thousand, one hundred eleven".
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