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14311354145 = 511260206439
BaseRepresentation
bin11010101010000010…
…11110111100100001
31100221101100010011112
431111001132330201
5213302201313040
610324033553105
71014435334364
oct152501367441
940841303145
1014311354145
116084428210
122934a15795
131470c839ba
1499a9a40db
1558b636365
hex35505ef21

14311354145 has 8 divisors (see below), whose sum is σ = 18734863680. Its totient is φ = 10408257520.

The previous prime is 14311354139. The next prime is 14311354219. The reversal of 14311354145 is 54145311341.

14311354145 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 14311354145 - 24 = 14311354129 is a prime.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 130103165 + ... + 130103274.

It is an arithmetic number, because the mean of its divisors is an integer number (2341857960).

Almost surely, 214311354145 is an apocalyptic number.

It is an amenable number.

14311354145 is a deficient number, since it is larger than the sum of its proper divisors (4423509535).

14311354145 is a wasteful number, since it uses less digits than its factorization.

14311354145 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 260206455.

The product of its digits is 14400, while the sum is 32.

Adding to 14311354145 its reverse (54145311341), we get a palindrome (68456665486).

The spelling of 14311354145 in words is "fourteen billion, three hundred eleven million, three hundred fifty-four thousand, one hundred forty-five".

Divisors: 1 5 11 55 260206439 1301032195 2862270829 14311354145