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14311412123 = 19753232217
BaseRepresentation
bin11010101010000011…
…01101000110011011
31100221101110001200212
431111001231012123
5213302210141443
610324035121335
71014435665411
oct152501550633
940841401625
1014311412123
116084467828
122934a4324b
131470ca41c8
1499a9bb2b1
1558b648618
hex35506d19b

14311412123 has 4 divisors (see below), whose sum is σ = 15064644360. Its totient is φ = 13558179888.

The previous prime is 14311412111. The next prime is 14311412191. The reversal of 14311412123 is 32121411341.

14311412123 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 14311412123 - 210 = 14311411099 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (14311417123) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 376616090 + ... + 376616127.

It is an arithmetic number, because the mean of its divisors is an integer number (3766161090).

Almost surely, 214311412123 is an apocalyptic number.

14311412123 is a deficient number, since it is larger than the sum of its proper divisors (753232237).

14311412123 is an equidigital number, since it uses as much as digits as its factorization.

14311412123 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 753232236.

The product of its digits is 576, while the sum is 23.

Adding to 14311412123 its reverse (32121411341), we get a palindrome (46432823464).

The spelling of 14311412123 in words is "fourteen billion, three hundred eleven million, four hundred twelve thousand, one hundred twenty-three".

Divisors: 1 19 753232217 14311412123