Base | Representation |
---|---|
bin | 11010101010000011… |
… | …10001011111111101 |
3 | 1100221101110222102012 |
4 | 31111001301133331 |
5 | 213302211231031 |
6 | 10324035341005 |
7 | 1014436102061 |
oct | 152501613775 |
9 | 40841428365 |
10 | 14311430141 |
11 | 608447a318 |
12 | 2934a51765 |
13 | 1470cac478 |
14 | 99a9c3aa1 |
15 | 58b64db2b |
hex | 3550717fd |
14311430141 has 2 divisors, whose sum is σ = 14311430142. Its totient is φ = 14311430140.
The previous prime is 14311430129. The next prime is 14311430143. The reversal of 14311430141 is 14103411341.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 11746007641 + 2565422500 = 108379^2 + 50650^2 .
It is a cyclic number.
It is not a de Polignac number, because 14311430141 - 222 = 14307235837 is a prime.
Together with 14311430143, it forms a pair of twin primes.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (14311430143) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7155715070 + 7155715071.
It is an arithmetic number, because the mean of its divisors is an integer number (7155715071).
Almost surely, 214311430141 is an apocalyptic number.
It is an amenable number.
14311430141 is a deficient number, since it is larger than the sum of its proper divisors (1).
14311430141 is an equidigital number, since it uses as much as digits as its factorization.
14311430141 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 576, while the sum is 23.
Adding to 14311430141 its reverse (14103411341), we get a palindrome (28414841482).
The spelling of 14311430141 in words is "fourteen billion, three hundred eleven million, four hundred thirty thousand, one hundred forty-one".
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