Base | Representation |
---|---|
bin | 11010101010001000… |
… | …00100001100100011 |
3 | 1100221102121111122122 |
4 | 31111010010030203 |
5 | 213302334443021 |
6 | 10324100254455 |
7 | 1014444153635 |
oct | 152504041443 |
9 | 40842544578 |
10 | 14312031011 |
11 | 608484a803 |
12 | 29350a142b |
13 | 147115cb05 |
14 | 99aadca55 |
15 | 58b71bbab |
hex | 355104323 |
14312031011 has 2 divisors, whose sum is σ = 14312031012. Its totient is φ = 14312031010.
The previous prime is 14312030969. The next prime is 14312031017. The reversal of 14312031011 is 11013021341.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 14312031011 - 214 = 14312014627 is a prime.
It is not a weakly prime, because it can be changed into another prime (14312031017) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (13) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7156015505 + 7156015506.
It is an arithmetic number, because the mean of its divisors is an integer number (7156015506).
Almost surely, 214312031011 is an apocalyptic number.
14312031011 is a deficient number, since it is larger than the sum of its proper divisors (1).
14312031011 is an equidigital number, since it uses as much as digits as its factorization.
14312031011 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 72, while the sum is 17.
Adding to 14312031011 its reverse (11013021341), we get a palindrome (25325052352).
The spelling of 14312031011 in words is "fourteen billion, three hundred twelve million, thirty-one thousand, eleven".
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