1431210121341 has 96 divisors (see below), whose sum is σ = 2607142965504. Its totient is φ = 679497984000.

The previous prime is 1431210121337. The next prime is 1431210121349.

1431210121341 is nontrivially palindromic in base 10.

It is not a de Polignac number, because 1431210121341 - 2² = 1431210121337 is a prime.

It is a super-2 number, since 2×1431210121341² (a number of 25 digits) contains 22 as substring.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1431210121349) by changing a digit.

It is a polite number, since it can be written in 95 ways as a sum of consecutive naturals, for example, 3121845 + ... + 3550821.

It is an arithmetic number, because the mean of its divisors is an integer number (27157739224).

Almost surely, 2^{1431210121341} is an apocalyptic number.

1431210121341 is a gapful number since it is divisible by the number (11) formed by its first and last digit.

It is an amenable number.

1431210121341 is a deficient number, since it is larger than the sum of its proper divisors (1175932844163).

1431210121341 is a wasteful number, since it uses less digits than its factorization.

1431210121341 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 429123 (or 429112 counting only the distinct ones).

The product of its (nonzero) digits is 576, while the sum is 24.

It can be divided in two parts, 1431210 and 121341, that added together give a palindrome (1552551).

The spelling of 1431210121341 in words is "one trillion, four hundred thirty-one billion, two hundred ten million, one hundred twenty-one thousand, three hundred forty-one".