14312112001 has 8 divisors (see below), whose sum is σ = 15633525600. Its totient is φ = 12994083840.

The previous prime is 14312111999. The next prime is 14312112019. The reversal of 14312112001 is 10021121341.

14312112001 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 14312112001 - 2¹ = 14312111999 is a prime.

It is not an unprimeable number, because it can be changed into a prime (14312112041) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 837511 + ... + 854428.

It is an arithmetic number, because the mean of its divisors is an integer number (1954190700).

Almost surely, 2^14312112001 is an apocalyptic number.

14312112001 is a gapful number since it is divisible by the number (11) formed by its first and last digit.

It is an amenable number.

14312112001 is a deficient number, since it is larger than the sum of its proper divisors (1321413599).

14312112001 is a wasteful number, since it uses less digits than its factorization.

14312112001 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1692719.

The product of its (nonzero) digits is 48, while the sum is 16.

Adding to 14312112001 its reverse (10021121341), we get a palindrome (24333233342).

The spelling of 14312112001 in words is "fourteen billion, three hundred twelve million, one hundred twelve thousand, one".